- 题解
2026.6.10题解
- @ 2026-7-10 19:07:42
1.舞蹈机器人
注:代码有我故意挖的坑,自己查
#include<bits/stdc++.h>
using namespace std;
#define int long long
signed main(){
int n;
cin>>n;
if(n%2==1){
cout<<(n/2+1)*(n/2+1);
}
else{
cout<<(1+((n+1)/2))*((n+1)/2)/2*4;
}
return 0;
}
1 条评论
-
summer_jindi @ 2026-7-10 19:09:51#include <bits/stdc++.h> using namespace std; int main(){ int n; cin >> n; int m = n/2+1; if (n%2==0) cout << m*m; else cout << (n+1)*(n+3)/2; }
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